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28x+24-(12x^2)=0
determiningTheFunctionDomain -12x^2+28x+24=0
a = -12; b = 28; c = +24;
Δ = b2-4ac
Δ = 282-4·(-12)·24
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-44}{2*-12}=\frac{-72}{-24} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+44}{2*-12}=\frac{16}{-24} =-2/3 $
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